Analysis of the Datos data, using Observaciones as the response variable and Fertilizantes as the single grouping factor.

Prepared by BrailleR

Group summaries

The ratio of the largest group standard deviation to the smallest is 4.11

Comparative boxplots

When boxplots are not included, it is because at least one group size is too small.

Comparative dotplots

Warning in dotplot.formula(Observaciones ~ Fertilizantes, xlab =
"Observaciones", : The dotplot command is a wrapper for stripchart, and is not a
base R function.

This graph has 5 dotplots printed horizontally
with the title: 
"" appears on the x-axis.
"" appears on the y-axis.
Tick marks for the x-axis are at: 45, 50, 55, and 60 
the data that range from 43 to 60 has been broken into 6 bins.
The counts are:
1: 0 0 6 0 0 0 
2: 0 0 0 0 4 1 
3: 2 1 1 1 0 0 
4: 1 2 1 0 0 0 
5: 3 3 0 0 0 0 

One-way Analysis of Variance

The p value for Fertilizantes is 0

The ratios of the group standard deviations to the overall standard deviation 
 (groups ordered by increasing mean) are:
 0.41 0.8 1.7 1 0.77

              Df Sum Sq Mean Sq F value   Pr(>F)    
Fertilizantes  4  439.9  109.97   23.57 1.65e-07 ***
Residuals     21   98.0    4.67                     
---
Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

Tests for homogeneity of Variance

    Bartlett test of homogeneity of variances

data:  Observaciones by Fertilizantes
Bartlett's K-squared = 8.091, df = 4, p-value = 0.0883

    Fligner-Killeen test of homogeneity of variances

data:  Observaciones by Fertilizantes
Fligner-Killeen:med chi-squared = 5.9346, df = 4, p-value = 0.2041

Tukey Honestly Significant Difference test

For term Fertilizantes the comparisons which are significant at 5% are:
1 and 5 with a difference of 5 and P-value of 0.0051 
2 and 5 with a difference of 12 and P-value of 0 
2 and 4 with a difference of 10 and P-value of 0 
2 and 3 with a difference of 9 and P-value of 0 
2 and 1 with a difference of 7 and P-value of 2e-04 

  Tukey multiple comparisons of means
    95% family-wise confidence level
    factor levels have been ordered

Fit: aov(formula = Observaciones ~ Fertilizantes, data = datos)

$Fertilizantes
    diff        lwr       upr     p adj
4-5    2 -2.1540691  6.154069 0.6135638
3-5    3 -0.8968622  6.896862 0.1862190
1-5    5  1.2844876  8.715512 0.0051458
2-5   12  8.1031378 15.896862 0.0000001
3-4    1 -3.3170352  5.317035 0.9564451
1-4    3 -1.1540691  7.154069 0.2364168
2-4   10  5.6829648 14.317035 0.0000074
1-3    2 -1.8968622  5.896862 0.5561272
2-3    9  4.9298601 13.070140 0.0000145
2-1    7  3.1031378 10.896862 0.0002309